How to get username from http basic authentication in OSB
OSB needs to start with following java option
-Dcom.bea.wli.sb.transports.http.GetHttpAuthorizationHeaderAllowed=true
Then use the following expression to get the authorization
header in osb
$inbound/ctx:transport/ctx:request/tp:headers/tp:user-header[@name='Authorization']/@value
Above value is in the base 64 encoded format. To decode :
Create a class as following, and use Java callout activity
package com.osb.custom.functions;
import javax.xml.bind.DatatypeConverter;
public class Base64Utitlity {
public
Base64Utitlity() {
super();
}
public static
String decode (String encodedStr) {
byte[]
decodedStr = DatatypeConverter.parseBase64Binary(encodedStr);
return new
String(decodedStr);
}
public static void
main(String[] args) {
Base64Utitlity
base64Utitlity = new Base64Utitlity();
}
}
To extract out the username , use following expression:
Input to java callout :
fn:substring-after($inbound/ctx:transport/ctx:request/tp:headers/tp:user-header[@name='Authorization']/@value,
' ')
Assign the java callout to a variable , say $temp
Then use following expression
fn:substring-before($temp, ':')
